Rationalize the denominator
4/2√11-√10
xipaham314:
plz
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Answer:
8root 11 + 4root 10/34
Step-by-step explanation:
4/2root 11- root 10
=4(2root 11+root 10)/(2root 11 -root 10)(2 root 11+ root 10). [multiplying the numerator and denominator by 2root 11 + root 10]
=8root 11 + 4root 10/ (2root 11)^2 - (root10)^2. [in denominator (a+b) (a-b)=a^2-b^2]
=8root 11 + 4root 10/(4*11) -10
= 8root 11 + 4root 10/44-10
= 8root 11 + 4root 10/34
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