Question

rationalize the denominator - (5-2root2)/(2+3root3)

Answer 1

Step-by-step explanation:

3√2/5√3X√3/√3

=3√6/3*5

=√6/5

Answer 2

Given :- Rationalize the denominator :- (5-2root2)/(2+3root3)

Answer :-

→ (5 - 2√2) / (2 + 3√3)

Multiply and divide by (2 - 3√3) we get,

→ {(5 - 2√2) / (2 + 3√3)} * {(2 - 3√3)/(2 - 3√3)}

→ (5-2√2)(2-3√3)/(2 + 3√3)(2 - 3√3)

using (a + b)(a - b) = a² - b² in denominator,

→ (10 - 15√3 - 4√2 + 6√6) / 2² - (3√3²)

→ (10 - 15√3 - 4√2 + 6√6) / (4 - 27)

→ (10 - 15√3 - 4√2 + 6√6) / (-23)

→ (15√2 + 4√2 - 6√6 - 10)/23 (Ans.)

Learn more :-

(7sqrt(3))/(sqrt(10+sqrt(3)))-(2sqrt(5))/(sqrt(6)+sqrt(5))-(3sqrt(2))/(sqrt(5)+3sqrt(2))

https://brainly.in/question/32043164

if the positive square root of (√190 +√ 80) i multiplied by (√2-1) and the

product is raised to the power of four the re...

https://brainly.in/question/26618255