Math, asked by aardraranganath, 5 hours ago

rationalize the denominator 5/√3-√2

Answers

Answered by MrPlatinum
3

Correct Question :-

Rationalise the denominator —

 \frac{5}{ \sqrt{3}  -   \sqrt{2}  }  \\

 \\

Correct Answer :-

The required solution is below;

 \frac{5}{ \sqrt{3}  -  \sqrt{2} }  \\

 \to \: \frac{5\left(\sqrt{3}+\sqrt{2}\right)}{\left(\sqrt{3}-\sqrt{2}\right)\left(\sqrt{3}+\sqrt{2}\right)}  \\

 \to \: \frac{5\left(\sqrt{3}+\sqrt{2}\right)}{\left(\sqrt{3}\right)^{2}-\left(\sqrt{2}\right)^{2}}  \\

 \to \: \frac{5\left(\sqrt{3}+\sqrt{2}\right)}{3-2}  \\

 \to \: \frac{5\left(\sqrt{3}+\sqrt{2}\right)}{1}  \\

 \to \: 5\left(\sqrt{3}+\sqrt{2}\right)  \\

 \to \: 5\sqrt{3}+5\sqrt{2}  \\

∴ Hence, the required rationalization of   \frac{5}{ \sqrt{3}  -   \sqrt{2}  }  \\ will be  5\sqrt{3}+5\sqrt{2}.

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