Math, asked by arnavk0056, 9 months ago

rationalize the denominator 5/3+root 5 -2root2

Answers

Answered by atahrv
3

Answer:

\frac{5}{6}\frac{3+\sqrt{5} +2\sqrt{2} }{1+\sqrt{5} }

Step-by-step explanation:

\frac{5}{3+\sqrt{5} -2\sqrt{2}  }

5(3+√5+2√2)/(3+√5-2√2)(3+√5+2√2)

5(3+√5+2√2)/(3+√5)²-(2√2)²

5(3+√5+2√2)/9+5+6√5-8

5(3+√5+2√2)/6+6√5

5(3+√5+2√2)/6(1+√5)

\frac{5}{6}\frac{3+\sqrt{5} +2\sqrt{2} }{1+\sqrt{5} }

Answered by akanshakathait
2

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