Question

Rationalize the denominator:
5+4 root 3 divided by 7+4root 3
Pls answer fast…
This is for my exam
Pls help
For The best answer , I will mark the brainliest

Answer 1

Answer:

5+43

1

 

Rationalize the denominator: \frac{5+4\sqrt{3}}{7+4\sqrt{3}} \cdot \frac{7-4\sqrt{3}}{7-4\sqrt{3}}=\frac{35-20\sqrt{3}+28\sqrt{3}-48}{{7}^{2}-{(4\sqrt{3})}^{2}}7+435+43⋅7−437−43=72−(43)235−203+283−48.

\frac{35-20\sqrt{3}+28\sqrt{3}-48}{{7}^{2}-{(4\sqrt{3})}^{2}}72−(43)235−203+283−48

2

 

Collect like terms.

\frac{(35-48)+(-20\sqrt{3}+28\sqrt{3})}{{7}^{2}-{(4\sqrt{3})}^{2}}72−(43)2(35−48)+(−203+283)

3

 

Simplify  (35-48)+(-20\sqrt{3}+28\sqrt{3})(35−48)+(−203+283)  to  -13+8\sqrt{3}−13+83.

\frac{-13+8\sqrt{3}}{{7}^{2}-{(4\sqrt{3})}^{2}}72−(4