Question

rationalize the denominator √6÷ √2+√3
​

Answer 1

$\huge\mathcal\color{teal}{Answer :- }$

Refer the attachment above ..

Hope it Helps !!

Answer 2

Step-by-step explanation:

$\frac{ \sqrt{6} }{ \sqrt{2} + \sqrt{3} } \times \frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} - \sqrt{3} }$

$\frac{ \sqrt{6} \times ( \sqrt{2} - \sqrt{3} )}{( \sqrt{2} + \sqrt{3} )( \sqrt{2} + \sqrt{3}) }$

$\frac{ \sqrt{12} - \sqrt{18} }{ ({ \sqrt{2} ) }^{2} - ({ \sqrt{3} }^{2} )}$

$\frac{2 \sqrt{3} - 3 \sqrt{2} }{2 - 3}$

$\frac{2 \sqrt{3} - 3 \sqrt{2} }{ - 1}$

$\frac{ - 2 \sqrt{3} + 3 \sqrt{2} }{1} = - 2 \sqrt{3 } + 3 \sqrt{2}$

hope it helps you

mark it brainliest please