Question

rationalize the denominator 6/2√3-√7​

Answer 1

Answer:

$\frac{12\sqrt{3}-6\sqrt{7} }{5}$

Step-by-step explanation:

$\frac{6}{2\sqrt{3}-\sqrt{7} }\\\frac{6}{{2\sqrt{3}-\sqrt{7} }}*\frac{{2\sqrt{3}+\sqrt{7} }}{{2\sqrt{3}+\sqrt{7} }} \\\frac{6({2\sqrt{3}-\sqrt{7} })}{{(2\sqrt{3}-\sqrt{7})({2\sqrt{3}+\sqrt{7}) } }} \\\frac{12\sqrt{3}-6\sqrt{7} }{(2\sqrt{3)} ^{2}-(\sqrt{7}) ^{2} }\\\frac{12\sqrt{3}-6\sqrt{7} }{12-7}\\\frac{{12\sqrt{3}-6\sqrt{7}}}{5}$

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