Question

rationalize the denominator
6÷√5+√2​

Answer 1

Hi ,

6/( √5 + √2 )

= [ 6( √5 - √2 ) ] / [ (√5 + √2 )(√5-√2)]

= [ 6( √5 - √2 ) ] / [ ( √5 )² - ( √2 )² ]

= [ 6(√5 - √2 ) ]/ ( 5 - 2 )

= [ 6(√5 - √2 ) ] / 3

= 2 ( √5 - √2 )

I hope this helps you.

:)

please mark as brainliest answer

Answer 2

Answer: 2 ($\sqrt{5} - \sqrt{2}$)

Step-by-step explanation: Multiply the numerator and denominator by ($\sqrt{5}$ - $\sqrt{2}$).

Using the identity (a + b) (a - b) = $a^{2} - b^{2}$, we get:

6 ($\sqrt{5} - \sqrt{2}$) / 5 - 2 or 2$\sqrt{5} - 2\sqrt{2}$) / 3 (Ans.)