Math, asked by bidishadas06, 8 months ago

rationalize the denominator
6÷√5+√2​

Answers

Answered by noorishahmed
2

Hi ,

6/( √5 + √2 )

= [ 6( √5 - √2 ) ] / [ (√5 + √2 )(√5-√2)]

= [ 6( √5 - √2 ) ] / [ ( √5 )² - ( √2 )² ]

= [ 6(√5 - √2 ) ]/ ( 5 - 2 )

= [ 6(√5 - √2 ) ] / 3

= 2 ( √5 - √2 )

I hope this helps you.

:)

please mark as brainliest answer

Answered by GrassBerry
0

Answer: 2 (\sqrt{5} - \sqrt{2})

Step-by-step explanation: Multiply the numerator and denominator by (\sqrt{5} - \sqrt{2}).

Using the identity (a + b) (a - b) = a^{2} - b^{2}, we get:

6 (\sqrt{5} - \sqrt{2}) / 5 - 2 or 2\sqrt{5} - 2\sqrt{2}) / 3 (Ans.)

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