Question

Rationalize the denominator : 7/√14

Answer 1

Answer:

7/√14

7/√14 *√14/√14

7(√14) /(√14) ²

7√14/14

So the answer to your question is 7√14/14

Answer 2

Answer:

Required fraction is

$\frac{ \sqrt{14} }{2}$

After rationalization of denominator.

Step-by-step explanation:

Given number is

$\frac{7}{ \sqrt{14} }$

We want to Rationalize the denominator of 7/√14.

But now question is how can we rationalize the denominator of any fraction.

We know,

We can rationalize denominator of any fraction by multiplication by

If we multiply denominator and numerator by denominator of any fraction then we can find a rational ize denominator of any fraction.

We are multiplying denominator and numerator by √14 and get

$\frac{7 \times \sqrt{14} }{ \sqrt{14} \times \sqrt{14} } \\ = \frac{7 \sqrt{14} }{14} \\ = \frac{ \sqrt{14} }{2}$

This is a problem of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x - + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

#SPJ2