Question

rationalize the denominator 7-3√2/7+3√2

Answer 1

do this by conjugating process

Answer 2

Answer:

Step-by-step explanation:

The given equation is:

$\frac{7-3\sqrt{2}}{7+3\sqrt{2}}$

Rationalizing the denominator, we have

$\frac{7-3\sqrt{2}}{7+3\sqrt{2}}{\times}\frac{7-3\sqrt{2}}{7-3\sqrt{2}}$

$\frac{(7-3\sqrt{2})^{2}}{(7)^{2}-(3\sqrt{2})^2}$

$\frac{(7-3\sqrt{2})^{2}}{49-18}$

$\frac{(7-3\sqrt{2})^{2}}{31}$

which is the required rationalized form.