Question

Rationalize the denominator 7/(√3−√2) if you answer fast i will mark you as brainlist​

Answer 1

Answer:

Step-by-step explanation:

={7/(√3−√2)}×{(√3+√2)/(√3+√2)}

={7×(√3+√2)} / {(√3-√2)×(√3+√2)}

={7×(√3+√2)} / {(3-2)}

={7×(√3+√2)} / {(1)} = {7×(√3+√2)}

Answer 2

$\begin{gathered}Hey\:ur\:answer!\\ \\ Solution:-\\ \\ \frac{7 }{\sqrt{3}-\sqrt{2}} \\ \frac{7}{\sqrt{3}-\sqrt{2}}×\frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}}\\ \\ Using\: Identities:\\ \\ ( a + b ).( a - b ) = a^{2} - b^{2} \\ \\ ( a - b ).( a - b ) = ( a - b )^{2}\\ \\ =\frac{7 (\sqrt{3}- \sqrt{2})}{(\sqrt{3}) ^2- (\sqrt{2})^{2}}\\ =7×\sqrt{3}+\sqrt{2}\end{gathered}$