Question

rationalize the denominator​

Answer 1

given :- (√3 + √5)/(√3 - √5)

= (√3 + √5)/(√3 - √5) × (√3 + √5)/(√3 + √5)

= [(√3 + √5)(√3 + √5)]/[(√3 - √5)(√3 + √5)]

using identity (a + b)(a - b) = a² - b² in denominator

= (√3 + √5)²/[(√3)² - (√5)²]

using identity (a + b)² = a² + 2ab + b² in numerator

= [(√3)² + 2(√3)(√5) + (√5)²]/(3 - 5)

= (3 + 2√15 + 5)/-2

= (8 + 2√15)/-2

dividing by 2 we get,

= (4 + 1√15)/-1

since denominator can't be negative.

= -(4 + √15)

= -4 - √15

Answer 2

Answer:

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