rationalize the denominator . a) 1/√7+√2 b)4/7+4√3
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Step-by-step explanation:
a) 1/√7+√2
1/√7+√2 × √7-√2/√7-√2
√7-√2/7-2
√7-√2/5
b) 4/7+4√3
4/7+4√3 × 7-4√3/7-4√3
4(7-4√3)/49-48
28-16√3
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ANSWER
7+34
The conjugate of7+3 is 7−3
=7+34×7−37−3
=7−34(7−3)
=7−3
Answered
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