Math, asked by kuldeeprandhawa51878, 10 months ago

Rationalize the denominator and simplify 2 root 6 minus root 5 upon 3 root 5 minus 2 root 6

Answers

Answered by Abhishek474241
6

AnSwEr

{\tt{\red{\underline{\large{Given}}}}}

  • \tt\red{\dfrac{2\sqrt{6}-\sqrt{5}}{3\sqrt{5}-2\sqrt{6}}}

{\sf{\green{\underline{\large{To\:find}}}}}

  • Rationalise

{\sf{\pink{\underline{\Large{Explanation}}}}}

  • \tt\dfrac{2\sqrt{6}-{\sqrt{5}}}{3\sqrt{5}-2{\sqrt{6}}}

Rationalising

  • Let understand
  • By step by step

\tt\dfrac{2\sqrt{6}-\sqrt{5}}{3\sqrt{5}-2\sqrt{6}}\times\dfrac{3\sqrt{5}+2\sqrt{6}}{3\sqrt{5}+2\sqrt{6}}

\implies\tt\dfrac{2\sqrt{6}-\sqrt{5}\times\:3\sqrt{5}+2\sqrt{6}}{45-24}

\implies\tt\dfrac{2\sqrt{6}-sqrt{5}\times\:3\sqrt{5}+2\sqrt{6}}{21}

=>2√6(3√5+2√6)-√5(3√5+2√6) / 21

=>6√30 + 24-15-2√30 / 21

=>(4√30-9)/ 21

Henece value be (4√30-9)/ 21

Answered by rajputyushra143
0

Answer:

....this is the answer

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