Rationalize the denominator and simplify.
2√x-3√y / √x+√y
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Hi
( 2√x - 3√y ) /(√x + √y )
= [(2√x-3√y)(√x -√y)]/[(√x+√y)(√x-√y)]
= [2x +2√xy -3√xy -3y]/[ (√x)² -(√y)²]
=[2x - √xy -3y ] / ( x - y )
I hope this helps you.
:)
( 2√x - 3√y ) /(√x + √y )
= [(2√x-3√y)(√x -√y)]/[(√x+√y)(√x-√y)]
= [2x +2√xy -3√xy -3y]/[ (√x)² -(√y)²]
=[2x - √xy -3y ] / ( x - y )
I hope this helps you.
:)
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