Question

rationalize the denominator and simplify √3-√2/√3+√2​

Answer 1

Answer:

$\sqrt{3 } - \sqrt{2} \div \sqrt{3 } + \sqrt{2}$

now multiplying both numerator and denominator with

$\sqrt{3} - \sqrt{2}$

Step-by-step explanation:

$( \sqrt{3} - \sqrt{2} ) {}^{2} \div ( \sqrt{3}) {}^{2} - ( \sqrt{2)} {}^{2}$

$3 + 2 - 2 \sqrt{6} \div 1$

hence,

$5 - 2 \sqrt{6}$

is the answee

Answer 2

Answer:

5-2√6

Step-by-step explanation:

√3-√2/√3+√2

=(√3-√2/√3+√2)*(√3-√2/√3-√2)

={(√3-√2)*(√3-√2)} / {(√3+√2)*(√3-√2)}

=(3+2-2√3*√2) / (3-2) [Since - (a-b) ^2= a^2+b^2-2ab

and (a+b) * (a-b) = a^2 - b^2]

=(5-2√6) / 1

=5-2√6