Question

rationalize the denominator by comparing a& b- (i)3+√2/3-√2=a+b√2


please help​

Answer 1

Answer:

$\frac{3 + \sqrt{2} }{3 - \sqrt{2} } = a + b \sqrt{2} \\ \frac{3 + \sqrt{2} }{2 - \sqrt{2} } \times \frac{3 + \sqrt{2} }{3 + \sqrt{2} } = a + b \sqrt{2} \\ \frac{(3 + \sqrt{2}) {}^{2} }{3 {}^{2} - ( \sqrt{2} ) {}^{2} } = a + b \sqrt{2} \\ \frac{3 {}^{2} + ( \sqrt{2} ) {}^{2} + 2 \times 3 \times \sqrt{2} }{9 - 2} = a + b \sqrt{2} \\ \frac{9 + 2 + 6 \sqrt{2} }{7} = a + b \sqrt{2} \\ \frac{11 + 6 \sqrt{2} }{7} = a + b \sqrt{2} \\ \frac{11}{7} + \frac{6 \sqrt{2} }{7} = a + b \sqrt{2} \\ a \: \: = \frac{11}{7} \\ b \: \: = \frac{6}{7}$

Answer 2

Step-by-step explanation:

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