Math, asked by Hammad6969, 3 months ago

rationalize the denominator of 1÷2-√3​

Answers

Answered by xInvincible
2

 \boxed{  \boxed{\boxed{2 +  \sqrt{3} }}}

Step-by-step explanation:

  =  > \frac{1}{2 -  \sqrt{3}  }  \\  =  >   \bf{l ets \: rationalize} \\  =  >  \frac{1}{2 -  \sqrt{3} }  \times  \frac{2 +  \sqrt{3} }{2 +  \sqrt{3} }  \\  =  >   \bf\color{red}{(x + y)(x - y) =  {x}^{2}  -  {y}^{2} } \\  =  >  \frac{2 +  \sqrt{3} }{ {2}^{2}  - ( \sqrt{ {3} }  {)}^{2} }  \\  =  >  \frac{2 +  \sqrt{3} }{4 - 3}  \\   \boxed{=  >  2 +  \sqrt{3}}

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