Question

.Rationalize the denominator of 1

2−√3​

Answer 1

Given:

• Number = $\frac{1}{2-\sqrt{3}}$

To Find:

• Rationalization of denominator.

Solution:

$→\;{\sf{\frac{1}{2-\sqrt{3}}}}$

$→\;{\sf{\frac{1}{2-\sqrt{3}}\times\frac{2+\sqrt{3}}{2+\sqrt{3}}}}$

✯ $\blue{\bold{(a-b)(a+b) = a²-b²}}$

$→\;{\sf{\frac{2+\sqrt{3}}{(2)²-(\sqrt{3})²}}}$

$→\;{\sf{\frac{2+\sqrt{3}}{4-3}}}$

$→\;{\sf{\frac{2+\sqrt{3}}{1}}}$

$➝\;{\bf{2+\sqrt{3}}}$

AnSweR:

Rationalization of $\frac{1}{2-\sqrt{3}}$ ◕➜ $\Large{\red{\mathfrak{2+\sqrt{3}\;✓}}}$

Hope It Helps You ✌️

Answer 2

Answer:

2 + √3

Hope it will help you...