rationalize the denominator of 1/√3-√2+1
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1/(√7+√3-√2). multiply numerator and denominator by (√7+√3+√2). =(√7+√3+√2)/[(√7+√3)-(√2)][( √7+√3)+(√2)]. =(√7+√3+√2)/(√7+√3)²-(√2)².
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1/(√7+√3-√2) multiply numerator and denominator by (√7+√3+√2) =(√7+√3+√2)/[(√7 ... More
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