Rationalize the denominator
of 1/(√3√2)
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Question is 1/(√3+√2)
ans :-
= 1/(√3 - √2) × √3+√2 /√3+√2
= √3 + √2 / [(√3)² - (√2)²]
= √3 + √2 / (3-2). (note: because when we multiply √ × √ then under root cut and the simple number is come ) .
= √3+√2 / 1
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