Rationalize the denominator of 1/4-√15
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Given,
x = \frac{1}{4 - \sqrt{15} }x=4−151
and,
y = \frac{1}{4 + \sqrt{15} }y=4+151
We have to find,
{x}^{3} + {y}^{3}x3+y3
Finding :
x = \frac{1}{4 - \sqrt{15} }x=4−151
Rationalising the denominator,
= > x = \frac{1}{4 - \sqrt{15} } \times \frac{4 + \sqrt{15} }{4 + \sqrt{15} }=>x=4−151×4+154+15
= > x = \frac{1 \times 4 + \sqrt{15} }{ ({4})^{2} - {( \sqrt{15}) }^{2} }=>x=(4)2−(15)21×4+15
= > x = \frac{4 + \sqrt{15} }{16 - 15}=>x=16−154+15
= > x = \frac{4 + \sqrt{15} }{1}=>x=14+15
= > x = 4 + \sqrt{15} \: \: \:=>x=4+15
Therefore, x = 4 + √15 (I)
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