Rationalize the denominator of 1/(4+2√3)
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Answered by
2
1/(4+2√3)
=1/{2(2+√3)}
=1/{2(2+√3)} * (2-√3)/(2-√3)
=(2-√3)/{2(2+√3)(2-√3)}
=(2-√3)/{2(4-3)} ; (a+b)(a-b)=a²-b²
=(2-√3)/2
=2/2 -√3/2
=1-√3/2
=1/{2(2+√3)}
=1/{2(2+√3)} * (2-√3)/(2-√3)
=(2-√3)/{2(2+√3)(2-√3)}
=(2-√3)/{2(4-3)} ; (a+b)(a-b)=a²-b²
=(2-√3)/2
=2/2 -√3/2
=1-√3/2
Answered by
2
=1/(4+2√3)
4+2√3=2(2+√3)
=1/[2(2+√3)]×(2-√3)/(2-√3)
=1(2-√3)/[2(2+√3)(2-√3)
=(2-√3)/2(2²-√3²)
=(2-√3)/2(4-3)
=(2-√3)/2(1)
=(2-√3)/2
=1-√3/2
Hope it helps
4+2√3=2(2+√3)
=1/[2(2+√3)]×(2-√3)/(2-√3)
=1(2-√3)/[2(2+√3)(2-√3)
=(2-√3)/2(2²-√3²)
=(2-√3)/2(4-3)
=(2-√3)/2(1)
=(2-√3)/2
=1-√3/2
Hope it helps
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