Question

Rationalize the denominator of 1/(7+3√2)

Answer 1

Step-by-step explanation:

1. 1/- 73682(/jsh u883822777+)///88376

Answer 2

Answer:

$7-3\sqrt{2}/31$

Step-by-step explanation:

$1/7+3\sqrt{2} \\= 1/7+3\sqrt{2} *7-3\sqrt{2} /7-3\sqrt{2} \\=7-3\sqrt{2} / (7+3\sqrt{2}) (7-3\sqrt{2})\\= 7-3\sqrt{2} /(7)^{2} - (3\sqrt{2)^{2} }$$( As ( a+ b)( a - b ) =a^{2} -b^{2} )$

$= 7-3\sqrt{2} /49 - (3*3*\sqrt{2} *\sqrt{2} )\\= 7 - 3\sqrt{2} / 49 - (9*2)\\= 7-3\sqrt{2} / 49 - 18\\= 7 - 3\sqrt{2} / 31$