Math, asked by pandeymedha026, 10 days ago

rationalize the denominator of 1/7+3√2​

Answers

Answered by AεѕтнεтícᎮѕуcнσ
2

Answer:

1/7+3-√2

= 1/7+3√2x 7-3√2/7-3√2

=7-3√2/ (7+3√2)(7-3-√2)

=7-3√2/(7)^2-(3-√2)^2

=7-3-√2/49-18

=7-3√2/31

Hope it helps! :)

Answered by bkbebybahen
2

Answer:

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