Rationalize the denominator of 1/√7+√6+√3
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first u have to do following step :
1/√7+√6+√3
=> 1/√7+(√6+√3)
=> now rationalize it as (a+b) (a-b) = (a)powered square - (b) powered square.
=> ur ans will be √7-√6-√3/-2+3√18 = √7-√6-√3/-(2-3√18) and again rationalize it
1/√7+√6+√3
=> 1/√7+(√6+√3)
=> now rationalize it as (a+b) (a-b) = (a)powered square - (b) powered square.
=> ur ans will be √7-√6-√3/-2+3√18 = √7-√6-√3/-(2-3√18) and again rationalize it
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