Question

rationalize the denominator of 1/√9-√8

Answer 1

Answer:

Step-by-step explanation:

root9=3

root 8= 2root 2

1/3-2root2

3

2root2

Answer 2

$\sf{\large \frac{1}{ \sqrt{9} - \sqrt{8} }} \\ \implies\sf{\large \frac{1}{ \sqrt{9 } - \sqrt{8} } \times \frac{ \sqrt{9} + \sqrt{8} }{ \sqrt{9} + \sqrt{8} } } \\ \implies\sf \large{ \frac{ \sqrt{9} + \sqrt{8} }{ {( \sqrt{9} )}^{2} - {( \sqrt{8} )}^{2} } } \\ \implies\sf \large{ \frac{ \sqrt{9} + \sqrt{8} }{ 9 - {8} } } \\ \fbox{\sf\large{ \sqrt{9} + \sqrt{8} }}$