Rationalize the denominator of 1 by root 7-root 6?
Answers
Answered by
0
Step-by-step explanation:
7
+
6
−
13
1
=
(
7
+
6
)
2
−13
7
+
6
+
13
=
2
42
7
+
6
+
13
=
12
6
+
14
7
+
84
546
Answered by
1
Answer:
Answer:
\sqrt{7}+\sqrt{6}
7
+
6
Explanation:
We have ,
\frac{1}{\sqrt{7}-\sqrt{6}}
7
−
6
1
Rationalising the denominator, we get
=\frac{(\sqrt{7}+\sqrt{6})}{(\sqrt{7}-\sqrt{6})(\sqrt{7}+\sqrt{6}}
(
7
−
6
)(
7
+
6
(
7
+
6
)
= \frac{(\sqrt{7}+\sqrt{6})}{(\sqrt{7})^{2}-(\sqrt{6})^{2}}
(
7
)
2
−(
6
)
2
(
7
+
6
)
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