Question

Rationalize the denominator of 1 upon root 6minus root 13

Answer 1

Hey friend,

Here is the solution :-

$\frac{1}{ \sqrt{6} - \sqrt{13} } \\ \\ \frac{1}{ \sqrt{6} - \sqrt{13} } + \frac{ \sqrt{6} + \sqrt{13} }{ \sqrt{6} + \sqrt{13} } \\ \\ \frac{ \sqrt{6} + \sqrt{13} }{( \sqrt{6})^{2} - ( \sqrt{13})^{2}} \: \: \: \: ((a + b)(a - b) = {a}^{2} - {b}^{2}) \\ \\ \frac{ \sqrt{6} + \sqrt{13} }{6 - 13} \\ \\ \frac{ \sqrt{6} + \sqrt{13} }{ - 7}$

Here, on rationalizing we get the result as -

$\frac{ \sqrt{6 } + \sqrt{13} }{ - 7}$

✨I hope this will help you....✨