Question

rationalize the denominator of 1 upon root 7 1 upon root 7 minus root 6 1 upon 5 root + root 2 1 upon root 7 minus 2rationalize the denominator of 1 upon root 7 ​

Answer 1

Answer:

[tex] i)\frac{1}{ \sqrt{7} } = \frac{ \sqrt{7} }{ \sqrt{7} \times \ \sqrt{7} } = \frac{ \sqrt{7} }{7} \\ ii) \frac{1}{ \sqrt{7} - \sqrt{6} } = \frac{ \sqrt{7} + \sqrt{6} }{( \sqrt{7} - \sqrt{6} )( \sqrt{7} + \sqrt{6} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{ \sqrt{7} + \sqrt{6} }{ { (\sqrt{7}) }^{2} - {( \sqrt{6} )}^{2} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{7} + \sqrt{6}

Others are same you can try yourself.