Question

rationalize the denominator of 13/root 27 minus root 14​

Answer 1

Answer:

The answer is root 27 + root 14

I hope this helps.

Answer 2

ANSWER,

$by \: rationalisation \: of \: denominator \\ \\ = > \frac{13}{ \sqrt{27} - \sqrt{14} } \\ \\ = > \frac{(13)( \sqrt{27} + \sqrt{14} ) }{( \sqrt{27} - \sqrt{14} )( \sqrt{27 + \sqrt{14} )} } \\ \\ ......by \: (x + y)(x - y) = x ^{2} - y ^{2} \\ \\ = > \frac{13 \sqrt{27 } + 13 \sqrt{14} }{( \sqrt{27} ) ^{2} - ( \sqrt{14} ) ^{2} } \\ \\ = > \frac{13 \sqrt{27} + 13 \sqrt{14} }{27 - 14} \\ \\ = > \frac{13( \sqrt{27 } + \sqrt{14} )}{13} \\ \\ = > ......cancelling \: 13 \: from \: numerator \: and \: denominator. \\ \\ = > \sqrt{27 } + \sqrt{14}$