rationalize the denominator of 1by root 5 +root 2
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1/√5+√2
(1/√5+√2)×√5-√2/√5-√2
=√5-√2/(√5)^2-(√2)^2
=√5-√2/5-2
=√5-√2/3
(1/√5+√2)×√5-√2/√5-√2
=√5-√2/(√5)^2-(√2)^2
=√5-√2/5-2
=√5-√2/3
ChrisRog:
Is it correct
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here is your answer. .......
hope it will help u ....☺
hope it will help u ....☺
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