Question

rationalize the denominator of 2/√3-1​

Answer 1

Answer:

$\sqrt{3 + 1}$

Answer 2

Answer:

$= \frac{2}{ \sqrt{3} - 1 } \\ \\ = \frac{2( \sqrt{3} + 1) }{( \sqrt{3} - 1)( \sqrt{3} + 1) } \\ \\ = \frac{2 \sqrt{3} + 2}{( \sqrt{3}) {}^{2} - (1) {}^{2} } \\ \\ = \frac{2 \sqrt{3} + 2}{3 - 1} \\ \\ = \frac{2 \sqrt{3} + 2}{2} \\ \\ = \frac{2( \sqrt{3} + 1) }{2} \\ \\ = \sqrt{3} + 1$

Step-by-step explanation:

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