Question

rationalize the denominator of 2/3√3

Answer 1

Solution:

To solve this problem

$\frac{2}{3 \sqrt{3} }$

We have to rationalized the denominator,by multiply and divide the complete number by √3.

By so we can eliminate irrational number from denominator,which is the main motive of rationalization.

So,

$\frac{2}{3 \sqrt{3} } \\ \\\\= \frac{2 \sqrt{3} }{3 \sqrt{3} \sqrt{3} } \\ \\\\= \frac{2 \sqrt{3} }{3 \times {\sqrt{3}}^2} \\\\\\ = \frac{2 \sqrt{3} }{3\times\:3}\\\\\\=\frac{2 \sqrt{3} }{9}$

Hope it helps you.

Answer 2

Answer:

$\frac{2\sqrt3}{9}$

Step-by-step explanation:

The given expression is $\frac{2}{3\sqrt3}$

In order to rationalize the denominator, we'll multiply numerator and denominator by $\sqrt3$

$\frac{2}{3\sqrt3}\cdot\frac{\sqrt3}{\sqrt3}$

On simplifying, we get

$\frac{2\sqrt3}{3\cdot3}\\\\=\frac{2\sqrt3}{9}$

The simplified expression is $\frac{2\sqrt3}{9}$