Math, asked by luckysanket8, 4 days ago

Rationalize the denominator of 2/√5+√3​

Answers

Answered by danishmahajan07
0

Answer:

2/√5 + √3

multiply both numerator and denominator by the conjugate of the denominator i.e. √5 - √3

=> 2(√5 - √3)/(√5 + √3)(√5 - √3)

=> 2(√5 - √3)/(5 - 3)

=> 2(√5 - √3 ) /2

=> √5 - √3

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Answered by AkashMathematics
1

{\color{#99ee99}{{\color{#99ee99}{ ☑ \:  Verified \: answer}}}}

Answer:-

 =  >  \boxed{ { \sqrt{5}  -  \sqrt{3} }{}  }

To find:-

Rationalize the denominator of

\frac{2}{ \sqrt{5}  +  \sqrt{3} }

Solution:-

Multiply both numerator and denominator by the conjugate of the denominator i.e. √5 - √3

 =  > \frac{2}{ \sqrt{5}  +  \sqrt{3} }\\  =  > \frac{2}{ \sqrt{5}  +  \sqrt{3} }  \times  \frac{\sqrt{5}   -   \sqrt{3}}{\sqrt{5}   -   \sqrt{3}}  \\  =  >  \frac{2\: (\sqrt{5}  -  \sqrt{3}) }{5 - 3}  \\ =  >  \frac{2\: (\sqrt{5}  -  \sqrt{3}) }{2}  \\\blue{ =  >{ \boxed { { \sqrt{5}  -  \sqrt{3} }{} }}}

\huge{\boxed{\mathcal\red{\fcolorbox{pink}{blue}{THANKS:-}}}}

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