Question

rationalize the denominator of √2\√7-2​

Answer 1

Answer:

please make my answer as brainest answer

Step-by-step explanation:

firstly, change the sign of the denominator , i.e √7 - √2 will become √7 + 2 , so multiply this term both with numerator and denominator. Multiply the terms , and we know that (a+b)(a-b) = a² - b² , use this identity for denominator! solve it more , square root and square will cancel out!

Answer 2

Answer:

$\frac{ \sqrt{2} }{ \sqrt{7} - 2} \\ multiply \: \frac{ \sqrt{7} + 2 }{ \sqrt{7} + 2 } \: to \: it \\ \frac{ \sqrt{2} \times ( \sqrt{7} - 2) }{( \sqrt{7} - 2)( \sqrt{7} - 2) } \\ = \frac{( \sqrt{14} - 2 \sqrt{2}) }{ { \sqrt{7} }^{2} - {2}^{2} } \\ = \frac{ \sqrt{14} - 2 \sqrt{2} }{7 - 4} = \frac{ \sqrt{14} - 2 \sqrt{2} }{3} \\ or \frac{ \sqrt{2} }{3} ( \sqrt{7} - 2)$