Question

rationalize the denominator of 2 by root 7 minus 3​

Answer 1

$= \frac{2}{ \sqrt{7} - 3} \times \frac{ \sqrt{7} + 3 }{ \sqrt{7 + 3} }$

$= \frac{2 \sqrt{7} + 6 }{ { (\sqrt{7}) }^{2} - {(3)}^{2} }$

$= \frac{2 \sqrt{7} + 6 }{7 - 9}$

$= \frac{2 \sqrt{7} + 6}{ - 2}$

$= - \sqrt{7} - 3$