Math, asked by abhishekmaurya0098, 10 months ago

Rationalize the denominator of 2-root3/3-root2

Answers

Answered by nandinigupta123
0

6+2root2-3root3-root6/7

Answered by vca1735
1

\frac{2 -  \sqrt{3} }{3 -  \sqrt{2} }  =  \frac{2 -  \sqrt{3} }{3 -  \sqrt{2} }  \times  \frac{3 +  \sqrt{2} }{3 +  \sqrt{2} }  = \frac{6 + 2 \sqrt{2}  -  3 \sqrt{3} +  \sqrt{6}   }{7}

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