Question

rationalize the denominator of √3+1/2√2-√3​

Answer 1

Answer:

answer= 2√2+1

Step-by-step explanation:

√3+1/2√2-√3

=√3+1/2√2-√3 root 3 divide

=2√2+1

Answer 2

Step-by-step explanation:

Given:-

$\frac{ \sqrt{3} + 1}{2 \sqrt{2} - \sqrt{3} }$

What to do:-

To rationalise the denominator.

Solution:-

Let's solve the problem,

we have

$\frac{ \sqrt{3} + 1}{2 \sqrt{2} - \sqrt{3} }$

✯The denominator is 2√2-√3. Multiplying the numerator and denominator by 2√2+√3. We get,

$⟹ \frac{ \sqrt{3} + 1 }{2 \sqrt{2} - \sqrt{3} } \times \frac{2 \sqrt{2} + \sqrt{3} }{2 \sqrt{2} + \sqrt{3} }$

$⟹ \frac{( \sqrt{3} + 1)(2 \sqrt{2} + \sqrt{3}) }{(2 \sqrt{2} - \sqrt{3} )(2 \sqrt{2} + \sqrt{3} ) }$

⬤ Applying Algebraic Identity

(a-b)(a+b) = a² - b² to the denominator

We get,

$⟹ \frac{({ \sqrt{3} + 1)(2 \sqrt{2} + \sqrt{3}) } }{(2 \sqrt{2} {)}^{2} - ( \sqrt{3} {)}^{2} }$

$⟹ \frac{( \sqrt{3} + 1)(2 \sqrt{2} + \sqrt{3} )}{8 - 3}$

$⟹ \frac{( \sqrt{3} + 1)(2 \sqrt{2} + \sqrt{3} )}{5}$

Now,

Multiplying the expressions in the numerator left side to right side.

$⟹ \frac{2 \sqrt{6} + 3 + 2 \sqrt{2} + \sqrt{3} }{5}$

Hence, the denominator is rationalised.

Answer:-

$\frac{2 \sqrt{6} + 3 + 2 \sqrt{2} + \sqrt{3} }{5}$

Used Formulae:-

• (a-b)(a+b) = a² - b²

:)