Question

Rationalize the denominator of 3−√2/ 3+√2

Answer 1

Step-by-step explanation:

Multiply with denominator with its opposite sign with numerator and denominator and solve it

Answer 2

Answer:

$\frac{11-6\sqrt{2} }{7}$

Step-by-step explanation:

given $\frac{3-\sqrt{2} }{3+{\sqrt{2} } }$

by rationalizing

$\frac{3-\sqrt{2} }{3+{\sqrt{2} } } \times \frac{3-\sqrt{2} }{3-{\sqrt{2} } }\\\frac{3-\sqrt{2} }{3+{\sqrt{2} } } \times \frac{3-\sqrt{2} }{3-{\sqrt{2} } }=\frac{3^2+(\sqrt{2} )^2-2\times 3\times \sqrt{2} }{3^2-\sqrt{2} }$

$=\frac{9+2-6\sqrt{2} }{9-2} \\\\=\frac{11-6\sqrt{2} }{7}$