rationalize the denominator of 3- √2 by 3 +√2
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3-√2/3+√2
=3-√2/3+√2 × 3-√2/3-√2
=9-√(2)²/(3+√2)(3-√2)
=9-2/(3)²-(√2)² [since, (a+b)(a-b)=a²-b²]
=7/9-2
=7/7
=1
HOPE YOU LIKE IT
=3-√2/3+√2 × 3-√2/3-√2
=9-√(2)²/(3+√2)(3-√2)
=9-2/(3)²-(√2)² [since, (a+b)(a-b)=a²-b²]
=7/9-2
=7/7
=1
HOPE YOU LIKE IT
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