Math, asked by mailaaryasankar, 3 months ago

rationalize the denominator of. 3/3 - 2√2​

Answers

Answered by Yuseong
3

 \Large {\underline { \sf \orange{Explication \: Of \: Steps :}}}

 \longrightarrow \sf{ \dfrac{3}{3 - 2 \sqrt{2} } }

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 \longrightarrow \sf{ \dfrac{3}{3 - 2 \sqrt{2} }  \times \dfrac{3 + 2 \sqrt{2} }{3  + 2 \sqrt{2} }}

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 \longrightarrow \sf{ \dfrac{3(3 + 2 \sqrt{2} )}{(3 - 2 \sqrt{2} )(3  + 2 \sqrt{2})} }

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 \longrightarrow \sf{ \dfrac{3(3 ) + 3(2 \sqrt{2}) }{  {3}^{2}   - ( 2 \sqrt{2})^{2}}}

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 \longrightarrow \sf{ \dfrac{9+ 6 \sqrt{2} }{  9   - ( 4  \times 2)}}

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 \longrightarrow \sf{ \dfrac{9+ 6 \sqrt{2} }{  9   - ( 8)}}

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 \longrightarrow  \boxed{\sf{ 9+ 6 \sqrt{2} }}

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❝ So, the answer is 9 + 62 is the answer. ❞

 \Large {\underline { \sf \orange{More \: Identities :}}}

• (√a)² = a

• √a√b = √ab

• √a/√b = √a/b

• (√a + √b)(√a - √b) = a - b

• (a + √b)(a - √b) = a² - b

• (√a ± √b)² = a ± 2√ab + b

• (√a + √b)(√c + √d) = √ac + √ad + √bc + √bd

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