Math, asked by spandhanavenkatesh05, 1 month ago

rationalize the denominator of : 3/√5-√2​

Answers

Answered by Yoyobrocome
0

Answer:

 \frac{3}{ \sqrt{5} -  \sqrt{2}  }  \\  \\  =  \frac{3}{ \sqrt{5} -  \sqrt{2}  }  \times  \frac{ \sqrt{5} +  \sqrt{2}  }{ \sqrt{5}  +  \sqrt{2} }  \\  \\  =  \frac{3 \sqrt{5}  + 3 \sqrt{2} }{( { \sqrt{5} }^{2} ) - ( { \sqrt{2} }^{2} )}  \\  \\  =  \frac{3 \sqrt{5} + 3 \sqrt{2}  }{5 - 2}  =  \frac{3 \sqrt{5}  + 3 \sqrt{2} }{3}

Similar questions