Math, asked by vinaymitrol, 1 year ago

rationalize the denominator of 3 by root 3 minus root 2

Answers

Answered by rakeshkumare
2
3/root3-root2 x root 3+root2/root3+root2

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Answered by BrainlyQueen01
10
hey mate!!

here's ur answer dear:-)
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 \frac{3}{ \sqrt{3}  -  \sqrt{2} }  \\  \\ \frac{3}{ \sqrt{3}  -  \sqrt{2} } \times  \frac{\sqrt{3}   +  \sqrt{2}}{ \sqrt{3}  +  \sqrt{2} }  \\  \\  \frac{3 \sqrt{3}  + 3 \sqrt{2} }{( \sqrt{3}) {}^{2}  - ( \sqrt{2}) {}^{2}   }  \\  \\  \frac{3 \sqrt{3}  + 3 \sqrt{2} }{3 - 2}  = 3\sqrt{3}  + 3 \sqrt{2}



hope it helps☺☺
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