Question

Rationalize the denominator of 3-root2/3+root2

Answer 1

*ANSWER*

⭕RATIONALIZE --

3 - √2 / 3 + √2

Multiply the numerator and the denominator with their rationalizing factor.

= (3 - √2)/(3 + √2) * (3 - √2)/(3 - √2)

= (3 - √2)^2 / (3)^2 - (√2)^2

= (3)^2 + (√2)^2 - 2*3*√2 / 9 - 2

= 9 + 2 - 6√2 / 7

= 11 - 6√2 / 7

Therefore after rationalisation , the answer will be...


11 - 6√2 / 7...

Thanks....☺✌

Answer 2

t3-√2/3+√2

lets rationalize multiply 3-√2 in both

(3-√2) / (3+√2) ×(3-√2)/ (3-√2)

(3-√2)^2/(3^2-√2^2)

(3^2+√2^2-2×3×√2) / (9-2)
(9+2-6√2)/ (7)

(11-6√2)/7

so your answer is 11-6√2/7

hope it helps you