Rationalize the denominator of 3-root2/3+root2
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Answered by
159
*ANSWER*
⭕RATIONALIZE --
3 - √2 / 3 + √2
Multiply the numerator and the denominator with their rationalizing factor.
= (3 - √2)/(3 + √2) * (3 - √2)/(3 - √2)
= (3 - √2)^2 / (3)^2 - (√2)^2
= (3)^2 + (√2)^2 - 2*3*√2 / 9 - 2
= 9 + 2 - 6√2 / 7
= 11 - 6√2 / 7
Therefore after rationalisation , the answer will be...
11 - 6√2 / 7...
Thanks....☺✌
⭕RATIONALIZE --
3 - √2 / 3 + √2
Multiply the numerator and the denominator with their rationalizing factor.
= (3 - √2)/(3 + √2) * (3 - √2)/(3 - √2)
= (3 - √2)^2 / (3)^2 - (√2)^2
= (3)^2 + (√2)^2 - 2*3*√2 / 9 - 2
= 9 + 2 - 6√2 / 7
= 11 - 6√2 / 7
Therefore after rationalisation , the answer will be...
11 - 6√2 / 7...
Thanks....☺✌
Answered by
68
t3-√2/3+√2
lets rationalize multiply 3-√2 in both
(3-√2) / (3+√2) ×(3-√2)/ (3-√2)
(3-√2)^2/(3^2-√2^2)
(3^2+√2^2-2×3×√2) / (9-2)
(9+2-6√2)/ (7)
(11-6√2)/7
so your answer is 11-6√2/7
hope it helps you
lets rationalize multiply 3-√2 in both
(3-√2) / (3+√2) ×(3-√2)/ (3-√2)
(3-√2)^2/(3^2-√2^2)
(3^2+√2^2-2×3×√2) / (9-2)
(9+2-6√2)/ (7)
(11-6√2)/7
so your answer is 11-6√2/7
hope it helps you
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