Rationalize the denominator of 3-root5/3+2root5
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Answer:
(9√5 - 19) / 11
Step-by-step explanation:
[3-√5] / [3+2√5]
⇒[(3-√5) / (3+2√5)] × [(3-2√5)/(3-2√5)] {Multiplying both numerator
and denominator with
conjugate of denominator}
⇒[(3-√5)(3-2√5)] / [(3+2√5)(3-2√5)]
⇒[3²+ 2(√5)² - 9√5] / [3² - (2√5)²]
⇒[9 + 10 -9√5] / [9-20]
⇒[19 - 9√5] / -11
⇒(9√5 - 19) / 11 {taking minus sign from denominator to
numerator, thus inversing + and - signs
in numerator}
Hope This Helps
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