Question

rationalize the denominator of 4/3+√(5)

Answer 1

Hi...☺

Here is your answer...✌

$\frac{4}{3 + \sqrt{5} } = \frac{4}{3 + \sqrt{5} } \times \frac{3 - \sqrt{5} }{3 - \sqrt{5} } \\ \\ = \frac{4(3 - \sqrt{5}) }{ {3}^{2} - {( \sqrt{5} )}^{2} } \\ \\ = \frac{4(3 - \sqrt{5} )}{9 - 5} \\ \\ = \frac{4(3 - \sqrt{5}) }{4} \\ \\ = 3 - \sqrt{5}$

Answer 2

Your answer is 3 - √5