Question

Rationalize the denominator of 4/3+root 3

Answer 1

Answer:

hope it helps you friend

Answer 2

The correct answer is $\frac{12-4\sqrt{3} }{6 }$.

Given: The term = $\frac{4}{3+\sqrt{3} }$.

To Find: Rationalize the denominator.

Solution:

$\frac{4}{3+\sqrt{3} }$

Divide and multiple the term by $3-\sqrt{3}$.

= $\frac{4}{3+\sqrt{3} }*\frac{3-\sqrt{3} }{3-\sqrt{3} }$

= $\frac{12-4\sqrt{3} }{3^{2} -\sqrt{3}^{2} }$

= $\frac{12-4\sqrt{3} }{9-3 }$

= $\frac{12-4\sqrt{3} }{6 }$

Hence, the answer is $\frac{12-4\sqrt{3} }{6 }$.

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