Question

rationalize the denominator of 4 root 3 + 3 root 2/ 6 root 2-3 root 5​

Answer 1

Step-by-step explanation:

(4√3+3√2)/(6√2-3√5)

on rationalising

(4√3+3√2)*(6√2+3√5) / (6√2-3√5)*(6√2+3√5)

4√3(6√2+3√5)+3√2(6√2+3√5) / [(6√2)^2 - (3√5)^2]

(24√6+12√15) + (18√4+9√10) / (72-45)

24√6+12√15+36+9√10 / 27