Question

rationalize the denominator of 5/√3-√5​

Answer 1

Answer:

(-5root3 - 5root5)/2

Step-by-step explanation:

5/root3 - root5 = 5/(root3 - root5) ×(root3 + root5)/(root3 + root5) = 5(root3 + root5)/(3 - 5) = (5root3 + 5root)/-2 = (-5root3 - 5root5)/2

Answer 2

Answer:

$\frac{5}{ \sqrt{3} -\sqrt{5} } = \frac{5}{ \sqrt{3} - \sqrt{5} } \times \frac{ \sqrt{3} + \sqrt{5} }{ \sqrt{3} + \sqrt{5} } \\ = \frac{5( \sqrt{3} + \sqrt{5} ) }{ { \sqrt{3} }^{2} - { \sqrt{5} }^{2} } = \frac{5( \sqrt{3} + \sqrt{5} ) }{3 - 5} \\ \frac{5( \sqrt{3} + \sqrt{5}) }{ - 2} = \frac{ - 5( \sqrt{3} + \sqrt{5} ) }{2}$

hope it will help you